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Normally a beam is analysed to obtain the maximum stress and this is compared to the
material strength to determine the design safety margin. It is also
normally required to calculate the deflection on the beam under the maximum expected
load. The determination of the maximum stress results from producing the
shear and bending moment diagrams. To facilitate this work the first
stage is normally to determine all of the external loads.
e = strain
To allow determination of all of the external loads a free-body diagram is construction with all of the loads and supports replaced by their equivalent forces. A typical free-body diagram is shown below.
The unknown forces (generally the support reactions) are then determined using the equations for plane static equilibrium.
For example considering the simple beam above the reaction R2 is determined by Summing the moments about R1 to zero
R2. L - W.a = 0 Therefore R2 = W.a / LR1 is determined by summing the vertical forces to 0
W - R1 - R2 = 0 Therefore R1 = W - R2
Shear and Bending Moment Diagram
The shear force diagram indicates the shear force withstood by the beam section along the length of the beam.
The sign convention used for shear force diagrams and bending moments is only important in that it should be used consistently throughout a project. The sign convention used on this page is as below.
A shear force diagram is simply constructed by moving a section along the beam
from (say)the left origin and summing the forces to the left of the section.
The equilibrium condition states that the forces on either side of a section balance
and therefore the resisting shear force of the section is obtained by this simple
The sketches below show Cantilever beams with three different load combinations.
Note: The force shown if based on loads (weights) would need to be converted to force units
i.e. 50kg = 50x9,81(g) = 490 N.
Consider a short length of a beam under a distributed load separated by a distance δx.
The bending moment at section AD is M and the shear force is S. The bending
moment at BC = M + δM and the shear force is S + δS.
S - w.δx = S + δS
Moments.. Taking moments about C
M + Sδx - M - δM - w(δx)2 /2 = 0
Therefore putting the relationships into integral form.
The integral (Area) of the shear diagram between any limits results in the change of the shearing force between these limits and the integral of the Shear Force diagram between limits results in the change in bending moment...
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Last Updated 15/01/2013