Introduction
An epicylic gear is a planetary gear arrangement consisting of one or more planet(epicyclic)
gears (P) meshed and rotating round a central sun gear (S). The planet gears
are also meshed and rotate within an internal ring gear (A). The planet gears
are fixed to a planet carriercrank arm(L) designed to rotate on the same centre as the sun
gear. Only one planetcarrier /crank arm is used in a single epicyclic gear train. This complicated arrangement (see below)
has a number of modes of operation depending on which members are locked. Epicyclic gears
can be based on spur gears, helical gears, or bevel gears.
Epicyclic gearboxes are generally purchased as complete units from specialist suppliers.
Design Features
 Coaxial drive and driven shafts
 Compact drive
 Low moment of Inertia
 Torque transmitted up to 10,000 Nm
 Drive speed up to 15,000 RPM
 Efficient
 Quiet in operation

Epicyclic Gearboxes (Planetary gearboxes)have the following features
Typical Epicyclic Gear Arrangement
There are three configurations possible with this epicylic gear
Star where the planet carrier arm is fixed and the sun and annulus ring gear rotate.
•Fixed frame assembly
•Input and output shaft rotate in opposite directions
•Ratios up to 10:1 (approx) (Reduction or increase depending on drive direction.)
Planetary where the annulus ring gear is the fixed component and the sun gear and planet carrier arm rotate
•Fixed annulus system
•Input and output shaft rotate in same directions
•Ratios up to 12:1 (approx) (Reduction or increase depending on drive direction.)
Solar where the sun gear is the fixed component and the annulus ring gear and planet carrier arm rotate.
•Fixed sunwheel
•Input and output shafts rotate is same direction
•Ratios up to 2:1 (approx)  (Reduction or increase depending on drive direction.)
Terminology
The terminology used below is N_{S}, N_{A}, N_{P} = number of teeth on
the sun wheel, the ring gear, and the plant gears respectively.
R_{S}, R_{A}, R_{L} R_{P} = rotation (revs) of the
the sun wheel, the ring gear, the planatory arm, and the plant gears respectively.
ω _{S} ,ω _{A} ,ω _{L},ω _{P}
= angular velocity of the sun wheel, the ring gear, the planatory arm, and the plant gears respectively.
If the ratio of rotation of the follower member (R_{A}) has a ratio of R relative to
the driving member (R_{B}) rotation i.e. R_{A} = R. R_{B}. Then R_{B} = R_{A} /R
Calculation of Ratios
Example 1.Planetary Arrangement.
The driver is the planetary arm ( L ).
The driven member is the Sun (S).
The Ring Gear is fixed. (A)
Note N_{A} = N_{S} + 2. N_{P}
Action  Rotation (CW= +ve) from action....................N_{x} = number of teeth 
L  A  P  S 
Turn whole gear thro 1 rev Clock Wise  1  1  1  1 
Fix arm L and rotate A back CCW 1 rev  0  1  N_{A} /N_{P}  +N_{A} / N_{S} 
Add the two motions above  1  0  1  ( N_{A} / N_{P})  1 + ( N_{A} / N_{S}) 
Summary : Rotation of the planet shaft(L) 1 rev CW results in the rotation of the
shaft (S) 1 + ( N_{A} / N_{S}) revs (CW). Ratio = R_{S} = R_{L} ( 1 + ( N_{A} / N_{S})
ratio r_{1} = R_{S} / R_{L} = ( 1 + ( N_{A} / N_{S})
Example 1a.. Arrangement as above
The driver is the Sun ( S ).
The driven member is the planetary arm (L).
The Ring Gear is fixed. (A)
The analysis is as above resulting in a ratio of R_{S} = R_{L} ( 1 + ( N_{A} / N_{S}) if the driver is the sun wheel
The ratio for this inverse arrangement is R_{L} = R_{S} / ( 1 + ( N_{A} / N_{S})
ratio r_{1a} = R_{L} / R_{S} = 1 / ( 1 + ( N_{A} / N_{S})

Example 2..Star Arrangement
The driver is the Sun ( S ).
The driven member is the Ring (A).
The planetary arm is fixed. (L)
Note N_{A} = N_{S} + 2. N_{P}
Action  Rotation (CW= +ve) from action....................N_{x} = number of teeth 
S  L  P  A 
Fix L and rotate Sun 1 rev CW  1  0   N_{S} / N_{P}   N_{S} / N_{A} 
Summary : Rotation of the Sun shaft(S) 1 rev CW results in the rotation of the shaft (A) N_{S} / N_{A} revs (CCW).
Ratio = R_{A} = R_{S}(  N_{S} / N_{A} )
ratio r_{2} = R_{A} / R_{S} =  ( N_{S} / N_{A})
Example 2a.. Arrangement as above
The driver is the ring gear ( A ).
The follower is the Sun (S).
The the planetary arm (L) is fixed. )
The analysis is as above resulting in a ratio of Ratio R_{A} = R_{S}(  N_{S} / N_{A} ) if the driver is the ring wheel
The ratios for this inverse arrangement is R_{S} = R_{A}(  N_{A} / N_{S} ))
ratio r_{2a} = R_{S} / R_{A} =  ( N_{A} / N_{S})

Example 3.Solar Arrangement..
The driver is the planetary Arm ( L ).
The follower is the annulus ring (A)
The the sun gear (S) is fixed.
Note N_{A} = N_{S} + 2. N_{P}
Action  Rotation (CW= +ve) from action....................N_{x} = number of teeth 
L  A  P  S 
Turn whole gear thro 1 rev Clock Wise  1  1  1  1 
Fix arm L and rotate S back CCW 1 rev  0  N_{S} /N_{A}  N_{S} /N_{P}  1 
Add the two motions above  1  1 + ( N_{S} / N_{A})  1 + ( N_{S} / N_{P})  0 
Summary : Rotation of the Planet arm L 1 rev CW results in the rotation of the Ring gear (A) 1 + ( N_{S} / N_{A})revs CW.
Ratio = R_{A} = R_{L} ( 1 + ( N_{S} / N_{A})
ratio r_{3} = R_{A} / R_{L} = ( 1 + ( N_{S} / N_{A})
Example 3a.. Arrangement as above
The driver is the annulus ring gear (A)
The follower is the planetary arm (L).
The sun ( S )is fixed.
The analysis is as above resulting in a ratio of
Ratio R_{A} = R_{L}.( 1 + ( N_{S} / N_{A}))
if the driver is the sun wheel and the follower is the planetary arm the resulting ratio
is R_{L} = R_{A} / ( 1 + ( N_{S} / N_{A})
ratio r_{3a} = R_{L} / R_{A} = 1 / ( 1 + ( N_{S} / N_{A})

Example 4..
The driver is the planetary Arm ( L ).
The follower is the sun (S).
The the Ring gear (A) is fixed.
Note N_{S} = N_{A}  N_{B} + N_{D}
Action  Rotation (CW= +ve) from action....................N_{x} = number of teeth 
L  A  BD  S 
Turn whole gear through 1 rev CW  1  1  1  1 
Fix L and rotate A back CCW 1 rev  0  1 
 N_{A} / N_{B}   ( N_{A} / N_{B}).( N _{D} / N _{S}) 
Add the two motions above  1  0  1 ( N_{A} / N_{B})  1  ( N_{A} . N_{D})/( N _{B} . N _{S}) 
Summary : Rotation of the Shaft L 1 rev CW results in the rotation of the shaft (S) 1  ( N_{A} . N_{D})/( N _{B} . N _{S}) revs (CW).
Ratio = R_{S} = R_{L} [1  ( N_{A} . N_{D})/( N _{B}. N _{S})]
ratio r_{4} = R_{S} / R_{L} = [1  ( N_{A} . N_{D})/( N _{B}. N _{S})]
Example 4a.. Arrangement as above
The driver is the sun ( S ).
The follower is the planetary arm (L).
The the Ring gear (A) is fixed. )
The analysis is as above resulting in a ratio of
Ratio R_{S} = R_{L}[1  ( N_{A} . N_{D})/( N _{B}. N _{S})]
if the driver is the sun wheel and the follower is the planetary arm the resulting ratio
is R_{L} = R_{S} / [1  ( N_{A} . N_{D})/( N _{B}. N _{S})]
ratio r_{4a} = R_{L} / R_{S} = 1 / [1  ( N_{A} . N_{D})/( N _{B}. N _{S})]

Example 5..
The driver is the planetary Arm ( L ).
The follower is the sun (S).
The the Ring gear (A) is fixed. )
Note N_{S} = N_{A}  N_{B}  N_{D}
Action  Rotation (CW= +ve) from action....................N_{x} = number of teeth 
L  A  BD  S 
Turn whole gear through 1 rev CW  1  1  1  1 
Fix L and rotate A back CCW 1 rev  0  1 
 N_{A} / N_{B}  + ( N_{A} / N_{B}).( N _{D} / N _{S}) 
Add the two motions above  1  0  1 ( N_{A} / N_{B})  1 + ( N_{A} . N_{D})/( N _{B} . N _{S}) 
Summary : Rotation of the shaft L 1 rev CW results in the rotation of the shaft (S) 1 + ( N_{A} . N_{D})/( N _{B} . N _{S}) revs (CW).
Ratio : R_{S} = R_{L} [1 + ( N_{A} . N_{D})/( N _{B} . N _{S})]
ratio r_{5} = R_{S} / R_{L} = [1 + ( N_{A} . N_{D})/( N _{B}. N _{S})]
Example 5a.. Arrangement as above
The driver is the sun ( S ).
The follower is the planetary arm (L).
The the Ring gear (A) is fixed. )
The analysis is as above resulting in a ratio of
Ratio R_{S} = R_{L}[1 + ( N_{A} . N_{D})/( N _{B}. N _{S})]
if the driver is the sun wheel and the follower is the planetary arm the resulting ratio
is R_{L} = R_{S} / [1 + ( N_{A} . N_{D})/( N _{B}. N _{S})]
ratio r_{5a} = R_{L} / R_{S} = 1 / [1 + ( N_{A} . N_{D})/( N _{B}. N _{S})]

Example 6..
The driver is the planetary Arm ( L ).
The follower is the sun (S).
The the Ring gear (A) is fixed.
Note N_{S} = N_{A} + N_{B} + N_{D}
Action  Rotation (CW= +ve) from action....................N_{x} = number of teeth 
L  A  BD  S 
Turn whole gear through 1 rev CW  1  1  1  1 
Fix L and rotate A back CCW 1 rev  0  1 
+ N_{A} / N_{B}  + ( N_{A} / N_{B}).( N _{D} / N _{S}) 
Add the two motions above  1  0  1 + ( N_{A} / N_{B})  1 + ( N_{A} . N_{D})/( N _{B} . N _{S}) 
Summary : Rotation of the shaft L  1 rev CW results in the rotation of the shaft (S) 1 + ( N_{A} . N_{D})/( N _{B} . N _{S}) revs (CW).
Ratio R_{S} = R_{L} [1 + ( N_{A} . N_{D})/( N _{B} . N _{S})]
ratio r_{6} = R_{S} / R_{L} = [1 + ( N_{A} . N_{D})/( N _{B}. N _{S})]
Example 6a.. Arrangement as above
The driver is the sun ( S ).
The follower is the planetary arm (L).
The the Ring gear (A) is fixed. )
The analysis is as above resulting in a ratio of
Ratio R_{S} = R_{L}[1 + ( N_{A} . N_{D})/( N _{B}. N _{S})]
if the driver is the sun wheel and the follower is the planetary arm the resulting ratio
is R_{S} = R_{L} / [1 + ( N_{A} . N_{D})/( N _{B}. N _{S})]
ratio r_{6a} = R_{L} / R_{S} = 1 / [1 + ( N_{A} . N_{D})/( N _{B}. N _{S})]

Example 7..
The driver is the planetary Arm ( L ).
The follower is the sun (S).
The the Ring gear (A) is fixed.
Note N_{S} = N_{A} + N_{B}  N_{D}
Action  Rotation (CW= +ve) from action...................... N_{x} = number of teeth 
L  A  BD  S 
Turn whole gear through 1 rev CW  1  1  1  1 
Fix L and rotate A back CCW 1 rev  0  1 
+ N_{A} / N_{B}   ( N_{A} / N_{B}).( N _{D} / N _{S}) 
Add the two motions above  1  0  1 + ( N_{A} / N_{B})  1  ( N_{A} . N_{D})/( N _{B} . N _{S}) 
Summary : Rotation of the shaft L 1 rev CW results in the rotation of the shaft (S) 1  ( N_{A} . N_{D})/( N _{B} . N _{S}) revs (CW).
Ratio 1: [1  ( N_{A} . N_{D})/( N _{B} . N _{S})]
ratio r_{7} = R_{S} / R_{L} = [1  ( N_{A} . N_{D})/( N _{B}. N _{S})]
Example 7a.. Arrangement as above
The driver is the sun ( S ).
The follower is the planetary arm (L).
The the Ring gear (A) is fixed. )
The analysis is as above resulting in a ratio of
Ratio R_{S} = R_{L}[1  ( N_{A} . N_{D})/( N _{B}. N _{S})]
if the driver is the sun wheel and the follower is the planetary arm the resulting ratio
is R_{L} = R_{S} / [1  ( N_{A} . N_{D})/( N _{B}. N _{S})]
ratio r_{7a} = R_{L} / R_{S} = 1 / [1  ( N_{A} . N_{D})/( N _{B}. N _{S})]

Epicyclic gear Train Variations
The figure below shows the range of possible epicylclic gear arrangements.. Those in
section I & III are classed as simple arrangements because the planet gears mesh with both sun gears.
Those in sections II & IV are classed as complex trains because the planet gears partially match with each other
and partially mesh with the sun gears.
Calculation of epicyclic Gear Ratio using Equations
1) First calculate the ratio of the gears with the planet carrier fixed..
r _{f} = (±) Product of
Driving Gear Teeth /Product of Driven Gear Teeth
Note: when two external gears are in contact there is a sign change (change of direction)
when an internal gear meshes with an external
gear both gears rotate in the same direction and there is no change in direction..
2) Designate and input gear (x) and an output gear (y).
The speed of the input gear relative to the carrier arm =
ω _{x}  ω _{L}
The speed of the output gear relative to the carrier arm =
ω _{y}  ω _{L}
3) The train value with the carrier fixed =
r _{f} =
( ω _{y}  ω _{L} ) / ( ω _{x}  ω _{L} )
This relationship is used to solve the planetary gear train ratios.
Using this method for the examples above
Example 1.
1) r _{f} = (N_{A} /N_{P} ).(  N_{P} /N_{S} )=  N_{A} /N_{S}
2) Select ω _{A} as input speed = 0 and ω _{S} as output speed (unknown) .
3) r _{f} =
( ω _{S}  ω _{L} ) / ( ω _{A}  ω _{L} )
Therefore  r _{f}.ω _{L} = ( ω _{S}  ω _{L} )
Therefore ω _{S}/ω _{L} = 1  r _{f}
ω _{S}/ω _{L} = 1 + N_{A} /N_{S}
Example 2.
1) r _{f} = (N_{S} /N_{P} ).( N_{P} /N_{A} )=  N_{S} /N_{A}
2) Select ω _{S} as input speed and ω _{A} as output speed .ω _{L} =0
3) r _{f} =
( ω _{A}  ω _{L} ) / ( ω _{S}  ω _{L} )
Therefore ω _{A} /ω _{S} = r _{f}
ω _{A}/ω _{S} =  N_{S} /N_{A}
Example 3.
1) r _{f} = (N_{S} /N_{P} ).( N_{P} /N_{A} )=  N_{S} /N_{A}
2) Select ω _{S} as input speed and ω _{L} as output speed .ω _{S} =0
3) r _{f} =
( ω _{A}  ω _{L} ) / ( ω _{S}  ω _{L} )
Therefore r _{f} = 1  ω_{A} / ω _{L}
resulting in ω_{A} / ω _{L} = N_{S} /N_{A} + 1.
ω _{A}/ω _{L} = 1 + N_{S} /N_{A}
Example 4.
1) r _{f} = (N_{A} /N_{B} ).(N_{D} /N_{S} )= ( N _{A}.N _{D}) / (N_{B} .N_{S} )
2) Select ω _{A} as input speed = 0 and ω _{S} as output speed.
(solve for ω _{S}/ ω _{L})
3) r _{f} =
( ω _{S}  ω _{L} ) / ( ω _{A}  ω _{L} )
Therefore 1  r _{f} = ω _{S} /ω _{L}
ω _{S}/ω _{L} = 1  ( N _{A}.N _{D}) / (N_{B} .N_{S} )
Example 5.
1) r _{f} = (N_{A} /N_{B} ).(  N_{D} /N_{S} )=  ( N _{A}.N _{D}) / (N_{B} .N_{S} )
2) Select ω _{A} as input speed = 0 and ω _{S} as output speed.
(solve for ω _{S}/ ω _{L})
3) r _{f} =
( ω _{S}  ω _{L} ) / ( ω _{A}  ω _{L} )
Therefore 1  r _{f} = ω _{S} /ω _{L}
ω _{S}/ω _{L} = 1 + ( N _{A}.N _{D}) / (N_{B} .N_{S} )
Example 6.
1) r _{f} = ( N_{A} /N_{B} ).( N_{D} /N_{S} )=  ( N _{A}.N _{D}) / (N_{B} .N_{S} )
2) Select ω _{A} as input speed = 0 and ω _{S} as output speed.
(solve for ω _{S}/ ω _{L})
3) r _{f} =
( ω _{S}  ω _{L} ) / ( ω _{A}  ω _{L} )
Therefore 1  r _{f} = ω _{S} /ω _{L}
ω _{S}/ω _{L} = 1 + ( N _{A}.N _{D}) / (N_{B} .N_{S} )
Example 7.
1) r _{f} = ( N_{A} /N_{B} ).( N_{D} /N_{S} )= ( N _{A}.N _{D}) / (N_{B} .N_{S} )
2) Select ω _{A} as input speed = 0 and ω _{S} as output speed.
(solve for ω _{S}/ ω _{L})
3) r _{f} =
( ω _{S}  ω _{L} ) / ( ω _{A}  ω _{L} )
Therefore 1  r _{f} = ω _{S} /ω _{L}
ω _{S}/ω _{L} = 1  ( N _{A}.N _{D}) / (N_{B} .N_{S} )
Calculating ratios by using the instantaneous planet gear velocities
This method analyses the motion of one planet gear. The centre moves at the same velocity as
the carrier , the pitch velocity at the teeth mating with ring is the same as that of the pitch velocity of the
ring and the pitch velocity of the teeth in contact with the sun gear moves at the same velocity as the
pitch velocity of the sun gear.
Looking for example at the Planetary arrangement the ring gear
is fixed v_{A} = 0 , the driver is the carrier with a speed v_{L} = ω _{L} R_{L}
Note: R_{L} = (R_{A}+ R_{S} ) /2
The velocity at the pitch line mating with the Sun wheel v_{S} is clearly 2.v_{L}.
From this relationship the gear ratios can easily be calculated as shown below.
