Singularity functions provide a compact method for representing concentrated forces, applied moments and distributed loads acting at different positions along a beam. They are particularly useful where several loading discontinuities would otherwise require separate equations for different regions of the beam.
Once the loading is represented by a singularity-function expression, successive integration can be used to obtain shear force, bending moment, slope and deflection throughout the beam.
For simple beam-loading arrangements, shear force and bending moment can usually be determined directly from equilibrium. More complicated loading may require different equations in different regions because concentrated loads, applied moments and changes in distributed loading create discontinuities.
Singularity functions provide a convenient method of incorporating these discontinuities into a single mathematical expression. The notation is closely related to the Macaulay method commonly used in elementary beam analysis.
A singularity function may be expressed in the general form:
where:
| Symbol | Description |
|---|---|
| x | Position along the beam measured from the selected origin |
| a | Position of the load or other discontinuity measured from the selected origin |
| n | Order of the singularity function |
For positive integer values of n, the function is zero before x = a and behaves as the normal algebraic expression (x − a)n after x reaches a.
For n > 0:
For n = 0 the singularity function represents a unit step:
Negative-order singularity functions are used to represent concentrated actions at x = a. In beam analysis the two particularly useful forms are:
| Function | Beam Action |
|---|---|
| Concentrated moment at x = a | |
| Concentrated force at x = a |
These negative-order terms are generalized functions concentrated at x = a and should not be interpreted simply as ordinary negative powers of (x − a).
For n ≥ 0:
This is the same integration rule as for an ordinary algebraic power.
For the negative-order beam singularities:
For n ≥ 1:
The following forms are commonly encountered when representing beam loads. The diagrams illustrate how the singularity function becomes active at x = a.
A concentrated moment M at x = a may be represented by:
Integrating once:
A concentrated force F at x = a may be represented by:
Integrating:
A uniform distributed load of intensity w0 beginning at x = a is represented by:
Integrating:
A linearly increasing distributed load beginning at x = a can be represented by a first-order singularity function:
where the coefficient must be selected to give the required load gradient.
A decreasing linear load can be constructed by combining a step function with a negative ramp. In unit form:
The coefficients and length scale must be selected to reproduce the required physical load distribution.
For n = 2:
Its integral is:
Consider a simply supported beam of span L carrying a concentrated load F at mid-span. By symmetry, each support reaction is F/2.
Taking the left-hand support as x = 0, the loading can be represented by:
Integrating once gives the shear-force expression:
Thus the shear force is +F/2 between the left support and the central load, and −F/2 between the central load and the right support.
Integrating again gives:
Within the beam span the final support term becomes active only at x = L. The expression therefore automatically describes the two bending-moment regions without requiring separate initial equations.
The maximum bending moment occurs at the centre:
Consider the simply supported beam shown below. A uniformly distributed load of intensity w acts from the left-hand support A to point B over a length a. The total beam span is L.
The objective is to obtain expressions for shear force, bending moment, slope and deflection at any position along the beam.
The resultant of the distributed load is wa and acts at a/2 from support A.
Taking moments about A:
Therefore:
and from vertical equilibrium:
The beam loading may be represented by:
The negative UDL term begins at x = 0. The corresponding positive term beginning at x = a cancels the distributed load beyond the end of the loaded region.
Integrating the load function gives:
For positions within the span, 0 < x < L:
Thus, over the loaded region 0 ≤ x ≤ a:
and beyond the distributed load, a ≤ x < L:
Integrating the shear-force expression gives:
For 0 ≤ x ≤ L:
For constant flexural rigidity EI, using EI d2y/dx2 = M(x), integration gives:
Integrating once more:
For the simply supported beam:
The first condition gives:
Applying y = 0 at x = L:
Therefore:
Substitution of the integration constants gives:
Finally, substituting R1 = wa(L − a/2)/L and rearranging:
This expression gives the beam deflection throughout the span 0 ≤ x ≤ L. The singularity term automatically becomes active when x reaches the end of the distributed load at x = a.